What is quadratic in standard form form y+9=2(x-1)^2?

Jul 25, 2016

$y = 2 {x}^{2} - 4 x - 7$

Explanation:

Quadratic equation in the standard form will be like this

$y = a {x}^{2} + b x + c$

Given -

$y + 9 = 2 {\left(x - 1\right)}^{2}$

$y + 9 = 2 \left({x}^{2} - 2 x + 1\right)$
$y + 9 = 2 {x}^{2} - 4 x + 2$
$y = 2 {x}^{2} - 4 x + 2 - 9$
$y = 2 {x}^{2} - 4 x - 7$