What is #S_n# for a geometric series that has #a_1 = .11 , a_5 = 895.956875, r = 9.5#?

1 Answer
Sep 24, 2017

# S_5 ~~1001.35#

Explanation:

Assuming #n=5# for which sum to be found.

We know sum of geometric series up to #n# th term is

#S_n = a_1* (r^n-1)/(r-1) # Here #a_1=0.11 , r=9.5 , n=5#

#:. S_5 = a_1* (r^5-1)/(r-1)= 0.11 * (9.5^5-1)/(9.5-1) ~~1001.35# [Ans]