What is #sqrt(-6)#?

1 Answer
kubik98
Jan 1, 2018

It's nonsense (in #RR#)

Explanation:

It's common property of squareroot that the number must be greater or equal to 0 in order to find squareroot (in real numbers #RR#)

There are so called imaginary numbers (#CC#) whose characteristics is: #i^2=-1# which is #i=sqrt(-1)#.

Then in #CC# it is: #sqrt(-6)=isqrt6#

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