What is #sqrt(8)+sqrt(18)-sqrt(32)#?

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Answer 1 · 2018-03-11T13:02:30

#9sqrt2#

Before we start, do you notice something? The numbers #8#, #18#, and #32# are perfect squares multiplied by #2#.

#sqrt8+sqrt18-sqrt32#

Split up the invidual square roots,

#(sqrt4xxsqrt2)+(sqrt9xxsqrt2)+(sqrt16xxsqrt2)#

Square root the perfect squares,

#2sqrt2+3sqrt2+4sqrt2#

Add them all up,

#9sqrt2#

Done :D