What is #sqrt(83)#?

1 Answer
Mar 29, 2016

#sqrt(83) ~~ 9.11043358#

Explanation:

#sqrt(83)# is an irrational number satisfying #sqrt(83)*sqrt(83) = 83#

Since #83# is a prime number, it has no square factors and #sqrt(83)# cannot be simplified.

It is not a whole number and cannot be represented in the form #p/q# for integers #p# and #q#.

In decimal form it is approximately #9.11043358#

It can be expressed as a simple continued fraction

#sqrt(83) = [9;bar(9, 18)] = 9+1/(9+1/(18+1/(9+1/(18+1/(9+1/(18+...))))))#

You can use this continued fraction to calculate approximations for #sqrt(83)# by truncating it.

For example, #sqrt(83) ~~ [9;9] = 9+1/9 = 9.111bar(1)#

For more accurate approximations, truncate later:

#sqrt(83) ~~ [9;9,18] = 9+1/(9+1/18) = 9+18/163 ~~ 9.11043#