What is the 30th term of the arithmetic series 2+7+12+17+...?

1 Answer
Dec 18, 2016

Answer:

The value of the #30^(th)# term in this arithmetic progression is 147

Explanation:

You are looking at what is called an arithmetic progression as the terms change by adding a common value (or common difference).

It is typical to write #t_n# as the #n^(th)# term in the progression, and #d# as the common difference. Then

#t_n# = #t_1# + (#n# - 1) #d#

Since, in this case, the common difference is #d#= 5 and #n# = 30 is the term we are looking for

#t_n# = 2 + (30 - 1) 5 = 2 + 145 = 147