What is the 30th term of the arithmetic series 2+7+12+17+...?

1 Answer
Dec 18, 2016

The value of the 30^(th) term in this arithmetic progression is 147

Explanation:

You are looking at what is called an arithmetic progression as the terms change by adding a common value (or common difference).

It is typical to write t_n as the n^(th) term in the progression, and d as the common difference. Then

t_n = t_1 + (n - 1) d

Since, in this case, the common difference is d= 5 and n = 30 is the term we are looking for

t_n = 2 + (30 - 1) 5 = 2 + 145 = 147