What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24?

1 Answer
Jan 20, 2016

Answer:

32nd term #a_32 = 128#

Explanation:

If #a_1# is first term, #d# is the common difference, and #a_n# is the #nth# term of an arithmetic sequence, then relationship between these is

#a_n = a_1 + (n – 1)d#

To find #d#, plug-in the given values
#a_6 = a_1 + (6 – 1)d#
#24 = 4 + (6 – 1)d#
Solving for #d# we obtain
#5d=20#
or #d=4#

To find 32nd term, plug-in appropriate values
#a_32 = 4 + (32 – 1)4#
#a_32 = 128#