What is the 3square root of 50 - square root of 32 + 6 square root of 128?

1 Answer
Sep 8, 2015

Answer:

#3sqrt(50)-sqrt(32)+6sqrt(128) = 59sqrt(2)#

Explanation:

Use #sqrt(ab) = sqrt(a)sqrt(b)# and #sqrt(a^2) = a# if #a >= 0#

#3sqrt(50)-sqrt(32)+6sqrt(128) =#

#3sqrt(5^2*2)-sqrt(4^2*2)+6sqrt(8^2*2)#

#3sqrt(5^2)sqrt(2)-sqrt(4^2)sqrt(2)+6sqrt(8^2)sqrt(2)#

#=(3*5)sqrt(2)-4sqrt(2)+(6*8)sqrt(2)#

#=(15-4+48)sqrt(2)#

#=59sqrt(2)#