Question

What is the acceleration at `t=2s` if the formula for velocity is `4+2t^3`?

Answer 1

see below

Explanation:

acceleration is velocity differentiated

`a=(dv)/(dt)`

`a=d/(dt)(4+2t^3)`

`(dv)/(dt)=6t^2`

`[(dv)/(dt)]_(t=2)=6xx2^2=24ms^(-2)`