What is the algebraic expression for the sum of three consecutive integer?

1 Answer
Oct 16, 2015

Sum of three consecutive integer number is 3 times the middle value: That is 3n given that the mean number is n.


Let any integer number be n
Then the number 1 less than it is n-1
Also the number 1 more than it is n+1

So the sum is #(n-1) + n + n(+1)#
Adding these we have #n+n+n+1-1#
So the final sum is #3n#

Note: the mean value is #3n/3 = n#