# What is the algebraic expression for the sum of three consecutive integer?

Oct 16, 2015

Sum of three consecutive integer number is 3 times the middle value: That is 3n given that the mean number is n.

#### Explanation:

Let any integer number be n
Then the number 1 less than it is n-1
Also the number 1 more than it is n+1

So the sum is $\left(n - 1\right) + n + n \left(+ 1\right)$
Adding these we have $n + n + n + 1 - 1$
So the final sum is $3 n$

Note: the mean value is $3 \frac{n}{3} = n$