What is the angle between #<3 , 2 , -1 > # and # < 1, -3 , 6 > #?

1 Answer
Mar 29, 2016

#alpha ~=69,23#

Explanation:

#A= <3,2,-1>" "B= <1,-3,6>#
#"steps..."#
#1-" find magnitude of A"#
#2-" find magnitude of B"#
#3-" find dot product "A*B#
#4-" use : "A*B=||A||*||B||*cos alpha#

#||A||=sqrt(3^2+2^2+(-1)^2)=sqrt(9+4+1)=sqrt14#
#||B||=sqrt(1^2+(-3)^2+6^2)=sqrt(1+9+36)=sqrt46#

#A*B=A_x*B_x+A_y*B_y+A_z*B_z#
#A*B=3*1+(2*(-3))+(-1*6)#
#A*B=3-6-6#
#A*B=-9#

#A*B=||A||*||B||*cos alpha#
#-9=sqrt14*sqrt46*cos alpha#
#cos alpha=-9/sqrt(14*46)#

#cos alpha=-9/(25,38)#
#cos alpha=0,3546099291#
#alpha ~=69,23#