What is the angle between #<3 , -2 , 7 > # and # < 1, -3 , 6 > #?
1 Answer
May 13, 2016
Explanation:
- Let First vector be
#vecA=3hati-2hatj+7hatk# #|vecA|=sqrt(3^2+2^2+7^2)=sqrt62# - and the 2nd vector be
#vecB=1hati-3hatj+6hatk# -
#|vecB|=sqrt(1^2+3^2+6^2)=sqrt46#
- If the angle between them be
#theta#
then#costheta=(vecA*vecB)/(|vecA||vecB|)#