What is the angle between <3 , -2 , 7 > and < 1, -3 , 6 > ?

1 Answer
May 13, 2016

=>theta =23.4^@

Explanation:

  • Let First vector be vecA=3hati-2hatj+7hatk
  • |vecA|=sqrt(3^2+2^2+7^2)=sqrt62
  • and the 2nd vector be vecB=1hati-3hatj+6hatk
    • |vecB|=sqrt(1^2+3^2+6^2)=sqrt46
  • If the angle between them be theta
    then costheta=(vecA*vecB)/(|vecA||vecB|)

=>costheta= ((3hati-2hatj+7hatk)*(1hati-3hatj+6hatk))/(sqrt62*sqrt46)

=>costheta= (1+6+42)/(sqrt62*sqrt46)~~0.92

=>theta =23.4^@