# What is the angle between <-3 , 5 ,2 >  and  < -2, 7 ,-2 > ?

The required angle is ${37.34}^{0}$
Let vecu =<-3,5, 2> and vecv =<-2,7,-2> ; theta be the angle between them ; then we know cos theta= (vecu*vecv)/(||vecu||*||vecv||)=((-3.-2)+(5*7)+(2* -2))/(sqrt((-3)^2+5^2+2^2)* sqrt((-2)^2+7^2+(-2)^2) $= \frac{37}{\sqrt{38} \cdot \sqrt{57}} = = 0.795 \therefore \theta = {\cos}^{-} 1 \left(0.795\right) = {37.34}^{0}$[Ans]