Question

What is the angle between `<5,9,-2 >` and `< 6,-2,7>`?

Answer 1

Angle between the vectors is `91.16^0`

Explanation:

Let `vecu =<5,9, -2> and vecv =<6,-2,7> ; theta` be the angle

between them ; then we know #cos theta= (vecu*vecv)/(||vecu||*||vecv||)=((5*6)+(9* -2)+(-2*7))/(sqrt(5^2+9^2+ (-2)^2)* (sqrt(6^2+(-2)^2+7^2))# #= -2/(sqrt110*sqrt89)==-0.02021336:. theta=cos^-1(-0.02021336)=91.16^0#[Ans]