Question

What is the angle between `<6 , 3 , 2 >` and `< 3 , -4 , 8 >`?

Answer 1

`theta`= arc cos 0.3331 = 70.54 degrees

Explanation:

Let vector u be <6,3,2> and v be <3,-4,8>. If `theta` is the angle between these two vectors, then
`cos theta= (u.v)/(||u|| ||v||` = `(6*3 -3*4+8*2)/(sqrt(6^2+3^2 +2^2).sqrt(3^2 +(-4)^2 +8^2))`

=`22/(7.sqrt89)` =0.3331

Hence `theta`= arc cos 0.3331 = 70.54 degrees