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What is the angle between #<6,8,1 ># and #< 4, 7, 3 >#?

1 Answer

A. S. Adikesavan

Feb 16, 2016

arccos ((cross product)/(product of the lengths of the vectors))
= arccos (83/(#sqrt101sqrt#74))
= 16.25 deg, nearly.

Explanation:

Here, the cross product = 6 X 4 = 8 x 7 +1 X 3 = 83. The lengths of the vectors are #sqrt#101 and #sqrt#74.

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