What is the angular momentum of a rod with a mass of #8 kg# and length of #6 m# that is spinning around its center at # 3 6 Hz#?

1 Answer
Feb 8, 2016

Answer:

#1728\pi=5428.6# #kg.m^2/s#

Explanation:

The moment-of-inertia of a rod of mass #M# and length #L# rotating about its centre is #I=1/12 ML^2=1/12(8kg)(6m)^2=24kg.m^2#.

The angular frequency #\omega# is related to the frequency #f# as #\omega = 2\pi f=2\pi*(36Hz)=72\pi# rad/s,

Angular Momentum : The magnitude of Angular Momentum vector is #L=I\omega = I.2\pi f=(24 kg.m^2)*(72\pi)=1728\pi# #kg.m^2/s#