What is the angular momentum of a rod with a mass of #8 kg# and length of #7 m# that is spinning around its center at #19 Hz#?

1 Answer
Jan 28, 2018

Answer:

#4387.23(kgm^2)/s#

Explanation:

The angular momentum of a rod is given by #L=Iomega#, where #I# is the moment of inertia and #omega# the angular velocity.

Furthermore, #I=1/12ml^2#, where #m# is the mass and #l# the length of the rod.

Also, #omega=2pif#, where #f# is the frequency.

Calculate #I#.

#I=1/12(8)(7)^2#
#color(white)I=3/4(49)#
#I=36.75kgm^2#

Calculate #omega#.

#omega=2pi(19)#
#omega=38pi(rad)/s#

Using these values, multiply:

#L=Iomega#
#L=36.75*38pi#
#L=4387.23(kgm^2)/s#