Question

What is the angular velocity in radians per second of a flywheel that spins 4820 revolutions per minute?

Answer 1

`omega~~505(rad)/s`

Explanation:

Given that the flywheel spins at `4820` revolutions per minute, we can convert this into radians per second, which will be equivalent to the angular velocity, `omega`.

Note that one revolution is equivalent to `2pi` radians.

`omega=(4820rev)/(min)xx(1min)/(60s)xx(2pirad)/(1rev)`

`omega=(482pi)/(3)(rad)/s~~505(rad)/s`