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Answer 1 · 2018-03-01T15:46:58

E. #=3x^8+6/x^4#

Given:

#y=1/3x^9-2/x^3-1#

#dy/dx=1/3(9x^8)-2(-3)/x^-4-0#

#=3x^8+6/x^4#

Answer 2 · 2018-03-01T15:47:58

#E#

Given, #y= 1/3 x^9 - 2/x^3 -1#

or, #y= 1/3 x^9 -2x^-3 -1#

so, #(dy)/(dx) = 9/3 x^8 - (-3)x^(-3-1)#

or, #(dy)/(dx) = 3x^8 + 6/x^4#