# What is the answer for volume used by 9.6g of SO2 gas at a pressure of 830 Pa and at a temperature of 327°C?

Jun 2, 2018

$901.5 \setminus \text{L}$

#### Explanation:

Molar mass of $\text{SO"_2 = 64\ "g/mol}$

Moles of $\text{SO"_2 = "9.6 g"/"64 g/mol" = "0.15 mol}$

From ideal gas equation

$\text{PV = nRT}$

$\text{V" = "nRT"/"P}$

color(white)("V") = "0.15 mol × 8.314 L kPa / (mol K) × 600 K"/"0.830 kPa"

color(white)("V") = 901.5\ "L"