# What is the antiderivative of 1/ x^2?

The antiderivative is the same as the integral, and I guess you want to compute $\int \frac{1}{x} ^ 2 \mathrm{dx}$. Since $\frac{1}{x} ^ 2 = {x}^{- 2}$, let's calculate the integral using the exponent algorythm:
$\int {x}^{- 2} \mathrm{dx} = {x}^{- 1} / \left(- 1\right) + C = - \frac{1}{x} + C$