What is the antiderivative of #1 / (x^2)#?

1 Answer
Dec 12, 2016

Answer:

#-1/x+c#

Explanation:

For this antiderivative, you would use the power rule for antiderivatives/integrals. This states that #int x^n = 1/(n+1)(x^(n+1))#. Since #1/x^2=x^-2# and #n!=-1# in this case, you can apply this power rule.

Answer: #int1/x^2 = intx^-2 = x^-1/-1 + c = -1/x + c#