What is the antiderivative of #g(x) = x ^ π#?

1 Answer
May 26, 2016

#1/(pi+1)x^(pi+1) + C#

Explanation:

Don't let #pi# throw you off. It's just a number. It's about 3.14.

What is the antiderivative of #x# to a constant power? (of #x# to a number?)

Add #1# to the exponent and divide by the new exponent. (And don't forget to add the constant).

The antiderivative of #x^pi# is #1/(pi+1)x^(pi+1) + C#