What is the antiderivative of #h(x) = cos x#?
1 Answer
Dec 6, 2016
Explanation:
Two really fundamental trig calculus properties are:
#d/dxsinx=cosx \ \ \ \ \ => intcosxdx=sinx+C# #d/dxcosx=-sinx => intsinxdx=-cosx+C#
So the anti derivative of
#inth(x)dx=intcosxdx=sinx+c#
