What is the antiderivative of # lnx/x^2#?
1 Answer
Sep 11, 2016
If we take this to be integration by parts, then, let:
#u = lnx#
#du = 1/xdx#
#dv = 1/x^2dx#
#v = -1/x#
#uv - intvdu#
#= -(lnx)/x - (- int 1/x^2dx)#
#= color(blue)(-(lnx)/x - 1/x + C)#
