What is the antiderivative of #m(x) = (-2/y^3)#? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Guillaume L. Aug 9, 2018 #M(x)=-2/y^3x+C#, #C in RR# Explanation: you have #m(x)=-2/y^3#, because m depends of x, you consider #-2/y^3# as a constant. So: #M(x)=intm(x)dx=int-2/y^3dx=-2/y^3x+C#, #C in RR# \0/ Here's our answer ! Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1642 views around the world You can reuse this answer Creative Commons License