Question

What is the antiderivative of `x/(x+1)`?

Answer 1

`x + ln abs(x+1) +C`
Note: This is the same answer as the one Selim has given. It just has a different constant.

Explanation:

`int x/(x+1) dx = int ((x+1)-1)/(x+1) dx`

`= int (1 - 1/(x+1))dx`

`= x +ln abs(x+1) +C`