Question

What is the approximate energy of a photon having a frequency of `4*10^7` `Hz`?

Answer 1

`E = 2.6xx10^(-26)J`

Explanation:

`color(coral)("To determine the answer, we will use the equation below:")`

We know h and v, so all we have to do is plug the known values into the equation and solve for E like this:

`E = (6.6xx10^(-34)Jxxcancels)xx(4xx10^(7)cancels^(-1))`

Thus, `E = 2.6xx10^(-26)J`

• I should also mention that the unit Hz is the same as `s^(-1)`, I wrote it that way because I wanted you to see how the units canceled out.