What is the arc length of #f(x) = (x^2-x)^(3/2) # on #x in [2,3] #?

1 Answer
Mar 1, 2016

#L = int_2^3 sqrt(1+9/4(x(x-1)(2x-1)^2)) dx#
Integrating we find (use Wolfram Alpha there is no closed integral for this integral):
L = 11.9145

Explanation:

We are going to use the Arc Length formula for L:
#L = int_a^bds#
where
#ds = sqrt(1+(dy/dx)^2) dx#
#L = int_a^b sqrt(1+(dy/dx)^2) dx#
so let's differentiate #y= f(x) = (x^2 - x)^(3/2)#
#dy/dx = f'(x) = 3/2 sqrt(x(x-1)) *(2x-1)#
Now find:
#(dy/dx)^2 = (f'(x))^2 = 9/4(x(x-1)(2x-1)^2) #
#L = int_2^3 sqrt(1+9/4(x(x-1)(2x-1)^2)) dx#
Integrating we find (use Wolfram Alpha there is no closed integral for this integral):
L = 11.9145