What is the area of a hexagon with sides of 3 feet in length?

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Answer 1 · 2016-02-13T07:21:19

The area of the hexagon is $"23.383 ft"^2"$ .

The formula for the area of a regular hexagon is: $A=((3sqrt3*s^2))/2$ , where $s$ is the length of each side.

Substitute the side length of $"3 ft"$ into the equation and solve.

$A=((3sqrt3*(3"ft")^2))/2$

$A=((3sqrt3*9"ft"^2"))/2$

$A="23.383 ft"^2"$ rounded to three decimal places