What is the area of a parallelogram with vertices (-2,1), (4,1), (3-2) and (-3-2)? Please show work.

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Answer 1 · 2015-12-05T15:05:10

#6 * 3 = 18#

#A = (-2, 1), B = (4, 1) Rightarrow |AB| = 6#

#C = (3, -2) Rightarrow |BC|^2 = 1^2+ 3^2 = 10#

#D = (-3, -2) Rightarrow |CD| = 6, |DA|^2 = 1^2 +3^2 = 10#

#ABCD# is indeed a paralelogram #Rightarrow# Area #= |CD| * h#

#AB: y = 1#

#CD : y = -2#

#h = dist(A, CD) = 3#