What is the area of a regular hexagon with side length of 8 m? Round your answer to the nearest tenth.

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Answer 1 · 2018-04-06T12:33:44

Area of the regular hexagon is $166.3$ square meter.

A regular hexagon is comprised of six equilateral triangles.

Area of an equilateral triangle is $sqrt3/4*s^2$ . Therefore,

area of a regular hexagon is $6*sqrt3/4*s^2 = 3sqrt3*s^2/2$

where $s=8$ m is the length of a side of the regular hexagon.

Area of the regular hexagon is $A_h=(3*sqrt3*8^2)/2$

$=96*sqrt3 ~~ 166.3$ square meter. [Ans]