What is the area of an isosceles right triangle with hypotenuse #6sqrt2#?

1 Answer

Since its a right isosceles triangle we have from Pythagoras' theorem

that

#a^2+a^2=(6sqrt2)^2=>2a^2=36*2=>a=6#

Hence the triangle has sides #6,6,6sqrt2#

Using Heron formula we can calculate the Area

#A=sqrt(s*(s-a)*(s-b)*(s-c))#

where #s=(a+b+c)/2#

a,b,c the sides of the triangle