Question

What is the average deviation of `1.76, 2.28, 1.90`?

Answer 1

mean deviation `=0.2`

Explanation:

Compute mean `barx`

`barx=(1.76+2.28+1.90)/3=1.98`

Mean deviation `=(sum abs(x-barx))/n`

Mean deviation `=(abs(1.76-1.98)+abs(2.28-1.98)+abs(1.90-1.98))/3`

Mean deviation `=0.2`

God bless....I hope the explanation is useful.