Question

What is the average value of a function `f(x)=3x^2 - 2` on the interval `[0,2]`?

Answer 1

The average value of `f` on interval `[a,b]` is `1/(b-a) int_a^b f(x) dx`

Explanation:

So the average value of `f(x) = 3x^2-2` on the interval `[(0,2]` is

`1/(2-0) int_0^2 (3x^2-2) dx`, `" "` which is `2`.