Question

What is the average value of the function `f(x)=18x+8` on the interval `[0,10]`?

Answer 1

`98`

Explanation:

The average value of `f` on `[a,b]` is

`1/(b-a) int_a^b f(x) dx`.

For this problem, that is

`1/(10-0) int_0^10 (18x+8) dx = 1/10 [9x^2+8x]_0^10`

`= 1/10[980] = 98`.