What is the axis of symmetry and coordinates of the vertex #y=4x^2-8x-3#?

1 Answer
Binayaka C.
Jul 29, 2016

Vertex is at #(1,-7)# Axis of symmetry is #x=1#

Explanation:

#y=4x^2-8x-3 =4(x^2-2x) -3= 4(x^2-2x+1) -4-3= 4(x-1)^2 -7#Comparing with general form #y=a(x-h)^2+k# we get vertex at#(h,k)=(1,-7)#The axis of symmetry is #x=1# graph{4x^2-8x-3 [-40, 40, -20, 20]}[Ans]

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