What is the binomial to the factor of #14a^2 - 15a + 4#?

1 Answer
Feb 27, 2018

#14a^2-15a+4 = (2a-1)(7a-4)#

Explanation:

We can factor the given quadratic as a product of binomials using an AC method:

First find a pair of factors of #AC = 14 * 4 = 56# with sum #B=15#

The pair #8, 7# works in that #8*7 = 56# and #8+7=15#

Use this pair to split the middle term and factor by grouping:

#14a^2-15a+4 = (14a^2-8a) - (7a-4)#

#color(white)(14a^2-15a+4) = 2a(7a-4) - 1(7a-4)#

#color(white)(14a^2-15a+4) = (2a-1)(7a-4)#