What is the center and radius of the circle with equation #(x-5)^2 + (y+6)^2 = 9#?
1 Answer
Jul 17, 2016
centre:
Explanation:
We can rewrite the given equation as:
#(x-5)^2+(y-(-6))^2=3^2#
This is of the form:
#(x-h)^2+(y-k)^2=r^2#
which is a standard form of the equation of a circle of radius
