What is the center, radius and diameter of this circle equation? x^2+ (y-6)^2 =169

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Answer 1 · 2018-05-09T18:24:55

#C(0, 6), R=13, D=26#

#x^2+(y-6)^2=169#

The standard equation of the circle center at:#(h, k)# and Radius #R#:

#(x-h)^2+(y-k)^2=R^2#

Thus in this case:

#(x-0)^2+(y-6)^2=(13)^2#

Center at#(0, 6)#, Radius is: #13# and the Diameter is just:

#D=2*R=2*13=26#