What is the change in volume when 4.8 L sample of #N_2(g)# is heated from 388.0°C to 700°C?

1 Answer
Feb 27, 2017

Answer:

We use #"Charles's Law"#, #VpropT#, we get #V_2~=7L#

Explanation:

If #VpropT#, then #V=kT#, and given the conditions (constant pressure, and constant amount of gas), we can solve for #k#:

#V_1/T_1=V_2/T_2#, where #T="temperatura assoluta"#

We solve for #V_2=V_1/T_1xxT_2#

#=(4.8*L)/(661*cancelK)xx973*cancelK =??L#