Question

What is the change in volume when 4.8 L sample of `N_2(g)` is heated from 388.0°C to 700°C?

Answer 1

We use `"Charles's Law"`, `VpropT`, we get `V_2~=7L`

Explanation:

If `VpropT`, then `V=kT`, and given the conditions (constant pressure, and constant amount of gas), we can solve for `k`:

`V_1/T_1=V_2/T_2`, where `T="temperatura assoluta"`

We solve for `V_2=V_1/T_1xxT_2`

#=(4.8*L)/(661*cancelK)xx973*cancelK =??L#