What is the charge on the particle given a #50xx10^-6# kg particle is released from rest in a region with a constant electric field of strength #"3000 N/C"#. If the particle is observed to accelerate at a rate of #"22 m/s"^2#?

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Answer 1 · 2018-03-13T03:48:43

#3.67 × 10^-7 "C"#

Force due to an electric field is

#F = Eq#

#a = F/m = (Eq)/m#

#q = (ma)/(E) = (50 × 10^-6 "kg" × "22 m/s"^2)/("3000 N/C") = 3.67 × 10^-7 "C"#