What is the complex conjugate of #2sqrt10#?

1 Answer
Dec 8, 2015

Answer:

#2sqrt10#

Explanation:

To find a complex conjugate, simply change the sign of the imaginary part (the part with the #i#). This means that it either goes from positive to negative or from negative to positive.

As a general rule, the complex conjugate of #a+bi# is #a-bi#.

You present an odd case. In your number, there is no imaginary component. Therefore, #2sqrt10#, if expressed as a complex number, would be written as #2sqrt10+0i#.

Therefore, the complex conjugate of #2sqrt10+0i# is #2sqrt10-0i#, which is still equal to #2sqrt10#.