What is the complex conjugate of #-4+sqrt2i#?

1 Answer
Nov 6, 2016

Answer:

#-4-sqrt2i#

Explanation:

The real and imaginary parts of a complex number are of equal magnitude to its conjugate, but the imaginary part is opposite in sign.

We denote the conjugate of a complex number, if the complex number is #z#, as #barz#

If we have the complex number #z=-4+sqrt2i#,

#Re(barz)=-4#

#Im(barz)=-sqrt2#

#:.barz=-4-sqrt2i#