What is the complex conjugate of #9-12i#?

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Answer 1 · 2016-12-15T19:06:04

It is #9+12i#

The complex conjugate of a complex number #z=a+bi# is a number with opposite imaginary part:

#bar(z)=a-bi#

So here we have:

#bar(z)=9-(-12i)=9+12i#