Question

What is the concentration (in M) of a solution that results from diluting 25.00 mL of 12 M HCI solution to 500.0 mL?

Answer 1

We gets `[HCl]=0.600*mol*L^-1`....

Explanation:

We use the relationship....

`"concentration"-="moles of solute"/"volume of solution"`

And here we dilute a `25.00*mL` volume of `12.0*mol*L^-1` `HCl` to a volume of `500.0*mL`...and note that the order of addition is important, because if you spit in acid it spits back, I kid you not....

And so....

`"concentration"-=(25.00xx10^-3*Lxx12.00*mol*L^-1)/(500*mLxx10^-3*L*mL^-1)=`

`=0.600*mol*L^-1` with respect to `HCl`...

The starting acid is VERY concentrated....the conc. laboratory reagent is approx. `10.6*mol*L^-1`...….