Question

What is the concentration of 10.00 mLof HBr if it takes 5 mL of a 0.253 M LiOH solution to neutralize it?

Answer 1

`"Concentration"` `~=` `0.1*mol*L^-1`

Explanation:

AS with all these problems, we need a stoichiometrically balanced equation:

`HBr(aq) + LiOH(aq) rarr LiBr(aq) + H_2O(l)`

So, there is `"1:1 molar equivalence"`

`[HBr]` `=` `(5xx10^-3*cancelLxx0.253*mol*L^-1)/(10.00xx10^-3*cancelL)` `=??mol*L^-1`