# What is the concentration of a lithium hydroxide solution that has a pOH of (3.1x10^0)? (answer to 2 s.d. in mol/L)

$\left[H {O}^{-}\right] = 3.1 \cdot m o l \cdot {L}^{-} 1$........
Since $p O H = - {\log}_{10} \left[H {O}^{-}\right] = - {\log}_{10} \left(3.1\right) = - 0.49 \cdot m o l \cdot {L}^{-} 1$