Question

What is the concentration of all ions present in the following solutions: 0.100 mole of `Ca(NO_3)_2` in 100.0 mL solution?

Answer 1

`3.00M`

Explanation:

Here's our concentration for multiplying the solvated ions by.

`(.100mol)/(.1000L) = 1.00M`

`Ca(NO_3)_2` is an ionic compound, thus it will completely dissolve in solution. Therefore,

`Ca^(2+)` and `2NO_3^-` will form.

`Ca^(2+)`: `1*1 = 1.00M`
`2NO_3^-`: `2*1 = 2.00M`

Summing all of these ions would give `3.00M`.