What is the concentration of all ions present in the following solutions: 0.100 mole of #Ca(NO_3)_2# in 100.0 mL solution?

1 Answer
Jun 28, 2017

Answer:

#3.00M#

Explanation:

Here's our concentration for multiplying the solvated ions by.

#(.100mol)/(.1000L) = 1.00M#

#Ca(NO_3)_2# is an ionic compound, thus it will completely dissolve in solution. Therefore,

#Ca^(2+)# and #2NO_3^-# will form.

#Ca^(2+)#: #1*1 = 1.00M#
#2NO_3^-#: #2*1 = 2.00M#

Summing all of these ions would give #3.00M#.